Acetamide, CH3CONH2, is warmed with Br2 + NaOH (Hofmann bromamide degradation). The organic product is

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Acetamide, $CH X_{3} CONH X_{2}$ , is warmed with $Br X_{2} + NaOH$ (Hofmann bromamide degradation). The organic product is

A $CH X_{3} COONa$
B $CH X_{3} CH X_{2} NH X_{2}$
C $CH X_{3} NH X_{2}$
D $CH X_{3} CN$

Answer: C

Hofmann degradation converts a primary amide RCONH2 into a primary amine R-NH2 with one carbon atom less. Acetamide has two carbons, so the amine is methylamine.

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Acetamide, $CH X_{3} CONH X_{2}$ , is warmed with $Br X_{2} + NaOH$ (Hofmann bromamide degradation). The organic product is