Reduction of ethanenitrile, CH3CN, with LiAlH4 followed by water gives

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Reduction of ethanenitrile, $CH X_{3} CN$ , with $LiAlH X_{4}$ followed by water gives

A $CH X_{3} NH X_{2}$
B $CH X_{3} CH X_{2} NH X_{2}$
C $(CH X_{3} CH X_{2}) X_{2} NH$
D $CH X_{3} CHO$

Answer: B

Complete reduction of the C-N triple bond in a nitrile gives a primary amine with the same number of carbon atoms as the nitrile, so CH3CN (2 C) gives ethylamine (2 C).

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Reduction of ethanenitrile, CHX3​CN, with LiAlHX4​ followed by water gives

Answer: B

More questions on Preparation of amines: Gabriel, Hofmann bromamide, reduction routes

Reduction of ethanenitrile, $CH X_{3} CN$ , with $LiAlH X_{4}$ followed by water gives