Answer: A, B, D
LiAlHX4 reduces CX6HX5CN to CX6HX5CHX2NHX2 and reduces CX6HX5CONHX2 to the amine with the same carbon count, again CX6HX5CHX2NHX2. Gabriel synthesis from benzyl chloride followed by hydrolysis also gives benzylamine. BrX2+NaOH on benzamide removes one carbon and gives aniline CX6HX5NHX2, not benzylamine.