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JEE Main levelNumerical answerDifficulty 2 of 3nc009

Benzamide, $C X_{6} H X_{5} CONH X_{2}$ (12.1 g), is converted to aniline, $C X_{6} H X_{5} NH X_{2}$ , by $Br X_{2} + NaOH$ with 72 percent yield. Using atomic masses H = 1, C = 12, N = 14, O = 16, calculate the mass of aniline obtained in grams, correct to two decimal places.

Numerical answer type, tolerance 0.02.

Answer: 6.7

Molar mass of benzamide

C X_{7} H X_{7} NO

is

84 + 7 + 14 + 16 = 121 g mo l^{- 1}

, so 12.1 g is 0.100 mol. One mole of amide gives one mole of aniline (molar mass

72 + 7 + 14 = 93

). Theoretical mass is

0.100 \times 93 = 9.30 g

, and at 72 percent yield the mass is

9.30 \times 0.72 = 6.70 g

.

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