20.0 g of Zn is added to 150 mL of 0.500 M H2SO4: Zn + H2SO4 -> ZnSO4 + H2. Find the volume of H2 at STP in litres (22.4 L/mol), to two decimals (Zn = 65).

JEE Main levelNumerical answerDifficulty 2 of 3mc193

$20.0 g$ of Zn is added to $150 mL$ of $0.500 M$ $H X_{2} SO X_{4}$ : $Zn + H X_{2} SO X_{4} ZnSO X_{4} + H X_{2}$ . Find the volume of $H X_{2}$ at STP in litres (22.4 L/mol), to two decimals (Zn = 65).

Numerical answer type, answer in L, tolerance 0.01.

n(Zn) = 20.0/65 = 0.308 mol; n(H2SO4) = 0.150 x 0.500 = 0.075 mol. The acid is limiting, so n(H2) = 0.0750 mol. Volume = 0.0750 x 22.4 = 1.68 L.