10.6 g of Na2CO3 reacts with excess HCl and 3.96 g of CO2 is collected. The percentage yield of CO2 is (Na = 23, C = 12, O = 16)

JEE Main levelSingle correct optionDifficulty 2 of 3mc190

$10.6 g$ of $Na X_{2} CO X_{3}$ reacts with excess HCl and $3.96 g$ of $CO X_{2}$ is collected. The percentage yield of $CO X_{2}$ is (Na = 23, C = 12, O = 16)

n(Na2CO3) = 0.10 mol gives 0.100 mol CO2 = 4.4 g theoretically. Yield = 3.96/4.4 x 100 = 90%.