JEE Advanced levelSingle correct optionDifficulty 3 of 3mt211
For 2Zn(g)+OX22ZnO(s) (T above 1180 K, the boiling point of Zn) take ΔG∘=−930+0.405T kJ, and for 2C+OX22CO, ΔG∘=−221−0.179T kJ. Carbon reduction of ZnO is first possible at about, and zinc is then obtained as
A3137 K; molten zinc that collects in the furnace hearth
B1751 K; zinc vapour that must be condensed
C1214 K; molten zinc that collects in the furnace hearth
D1214 K; zinc vapour that must be condensed
Answer: D
Set the two lines equal: −930+0.405T=−221−0.179T, so 709=0.584T and T=1214 K. This is above the boiling point of zinc (1180 K), so zinc leaves the furnace as vapour and is condensed.