JEE Main levelSingle correct optionDifficulty 2 of 3mt208
Take ΔG∘=−529+0.131T kJ for 2Fe+OX22FeO and ΔG∘=−221−0.179T kJ for 2C+OX22CO. Reduction of FeO by carbon, FeO+CFe+CO, becomes spontaneous above approximately
A994 K
B1235 K
C6417 K
D4038 K
Answer: A
For FeO+CFe+CO, ΔG∘=21[(−221−0.179T)−(−529+0.131T)]=21(308−0.310T) kJ. This is zero at T=308/0.310=994 K, and negative above it.