JEE Advanced levelSingle correct optionDifficulty 3 of 3mt214
Using ΔGf∘ at 298 K (kJ/mol): FeX2OX3−742.2; CO−137.2; COX2−394.4, calculate ΔG∘ and log10K for FeX2OX3+3CO2Fe+3COX2 at 298 K (R=8.314JK−1mol−1).
A-9.8 kJ; log10K=1.72
B-29.4 kJ; log10K=5.15
C+29.4 kJ; log10K=−5.15
D-29.4 kJ; log10K=11.87
Answer: B
ΔG∘=3(−394.4)−(−742.2)−3(−137.2)=−29.4 kJ. log10K=−ΔG∘/(2.303RT)=29400/(2.303×8.314×298)=5.15. The reduction by CO is thermodynamically favourable even at 298 K, though slow.