JEE Advanced levelSingle correct optionDifficulty 3 of 3nm244
What is the IUPAC name of the compound shown? Numbering starts from the principal group.
A4-oxopent-2-enoic acid
B3-oxopent-1-en-5-oic acid
C3-oxopent-4-enoic acid
D3-oxopentanoic acid
Answer: C
The compound is 3-oxopent-4-enoic acid. The acid is principal (C1), then the ketone is a prefix oxo at C3 and the double bond lies at C4. Numbering from the vinyl end (pent-1-en-5-oic acid) breaks the rule that the principal group gets C1.