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JEE Advanced levelSingle correct optionDifficulty 3 of 3nm244

What is the IUPAC name of the compound shown? Numbering starts from the principal group.

  1. A4-oxopent-2-enoic acid
  2. B3-oxopent-1-en-5-oic acid
  3. C3-oxopent-4-enoic acid
  4. D3-oxopentanoic acid

Answer: C

The compound is 3-oxopent-4-enoic acid. The acid is principal (C1), then the ketone is a prefix oxo at C3 and the double bond lies at C4. Numbering from the vinyl end (pent-1-en-5-oic acid) breaks the rule that the principal group gets C1.
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