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JEE Main levelSingle correct optionDifficulty 2 of 3nm241

What is the IUPAC name of the compound shown?

  1. A4-methoxybutan-3-one
  2. B1-methoxybutan-2-one
  3. C1-ethoxypropan-2-one
  4. D4-methoxybutan-2-one

Answer: B

The compound is 1-methoxybutan-2-one. The ketone is the principal group and must get the lowest locant: numbering from the methoxy-bearing end puts C=O at 2 (against 3 from the other end). The ether oxygen is only a methoxy prefix on C1.
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