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JEE Main levelSingle correct optionDifficulty 2 of 3nm242

What is the IUPAC name of the compound shown?

  1. Apent-3-en-2-ol
  2. Bpent-4-en-2-ol
  3. Cpent-4-en-1-ol
  4. Dpent-1-en-4-ol

Answer: B

The compound is pent-4-en-2-ol. The alcohol is the principal group, so it gets the lowest locant (2) even though that leaves the double bond at 4. The name pent-1-en-4-ol numbers to favour the double bond, which is wrong.
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