JEE Advanced levelOne or more correct optionsDifficulty 3 of 3ie216
For saturated Ca(OH)X2 at 298 K with Ksp=4.0×10−6 (no other source of OHX− or CaX2+, activities ignored), choose the correct statement(s).
AIn pure water [OHX−]=2.0×10−2M
BIn 0.010MNaOH the solubility is about 7.0×10−3M
CIn 0.010MCaClX2 the solubility is about 2.3×10−2M
DThe solubility in 0.010MNaOH is greater than in pure water
Answer: A, B
In water s=(Ksp/4)1/3=1.0×10−2M and [OHX−]=2s=0.020M. In 0.010MNaOH, solving s(0.010+2s)2=Ksp gives s=7.0×10−3M, lower than in water. In 0.010MCaClX2, (0.010+s)(2s)2=Ksp gives s=7.5×10−3M, not three times that.