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JEE Advanced levelOne or more correct optionsDifficulty 3 of 3ie217

Using $K_{s p} (AgCl) = 1.8 \times 1 0^{- 10}$ and ignoring interionic effects, choose the correct statement(s) about the solubility of $AgCl$ .

AIt is lower in $0.1 M$ $CaCl X_{2}$ than in $0.1 M$ $NaCl$
BIt is the same in $0.1 M$ $AgNO X_{3}$ as in $0.1 M$ $NaCl$
CIt is practically the same in $0.1 M$ $KNO X_{3}$ as in pure water
DIt is $1.3 \times 1 0^{- 7}$ $M$ in $0.1 M$ $NaCl$

Answer: A, B, C

Solubility

= K_{s p} / c

for the common ion:

0.1 M

NaCl

and

0.1 M

AgNO X_{3}

both give

1.8 \times 1 0^{- 9}

M

, and

0.1 M

CaCl X_{2}

(

[Cl X^{-}] = 0.2

) gives

9.0 \times 1 0^{- 10}

M

.

KNO X_{3}

has no common ion, so

s = 1.3 \times 1 0^{- 5} M

. The value

1.3 \times 1 0^{- 7}

does not arise.

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