JEE Advanced levelNumerical answerDifficulty 3 of 3ie209
What mass of AgX2CrOX4 (molar mass 332gmol−1, Ksp=1.1×10−12) dissolves in 250mL of 0.020MKX2CrOX4? Neglect the chromate contributed by the salt itself. Give the answer in mg (two decimals).
Numerical answer type, answer in mg, tolerance 0.02.
Answer: 0.31 mg
[CrOX4X2−]≈0.020M, so [AgX+]=1.1×10−12/0.020=7.4×10−6M. Dissolved salt =[AgX+]/2=3.7×10−6M. Mass =3.7×10−6×332×0.250=0.31mg (after converting g to mg).