The increase in the translational kinetic energy of $2.0 mol$ of an ideal gas when its temperature is raised from $300 K$ to $400 K$ , taking $R = 8.314 J K^{- 1} mo l^{- 1}$ , in joules (nearest integer) is

Numerical answer type, answer in J, tolerance 1.

Answer: 2494 J

Δ K E = \frac{3}{2} n R Δ T = 1.5 \times 2.0 \times 8.314 \times 100 = 2494.2 \approx 2494 J