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JEE Main levelSingle correct optionDifficulty 2 of 3ig180

$0.5 mol$ of $He$ and $1.5 mol$ of $Ne$ are placed in a vessel at $300 K$ and the total pressure is $4 atm$ . If $He$ is removed, keeping $T$ and $V$ constant, the pressure becomes

A $3 atm$
B $1 atm$
C $2 atm$
D $4 atm$

Answer: A

p_{Ne} = x_{Ne} P = \frac{1.5}{2.0} \times 4 = 3 atm

. Removing He leaves only this partial pressure.

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