300 mL of N2 is collected over water at 25 degC and 755 mm Hg. The aqueous tension at 25 degC is 25 mm Hg. The volume of dry N2 at STP (273 K, 760 mm Hg) in mL (one decimal) is

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$300 mL$ of $N X_{2}$ is collected over water at $2 5^{\circ} C$ and $755 mm Hg$ . The aqueous tension at $2 5^{\circ} C$ is $25 mm Hg$ . The volume of dry $N X_{2}$ at STP ( $273 K$ , $760 mm Hg$ ) in mL (one decimal) is

Numerical answer type, answer in mL, tolerance 0.2.

p_{N X_{2}} = 755 - 25 = 730 mm Hg

V_{STP} = 300 \times \frac{730}{760} \times \frac{273}{298} = 263.984 \approx 264.0 mL