$10 mL$ of $C X_{2} H X_{4}$ is exploded with $40 mL$ of $O X_{2}$ and the products are cooled to room temperature. The contraction in volume in mL (nearest integer) is

Numerical answer type, answer in mL, tolerance 0.5.

Answer: 20 mL

C X_{2} H X_{4} + 3 O X_{2} 2 CO X_{2} + 2 H X_{2} O (l)

. Initial gas

= 50 mL

. After reaction:

CO X_{2}

20

, leftover

O X_{2}

40 - 30 = 10

, total

30 mL

. Contraction

= 50 - 30 = 20 mL

(equals twice the volume of hydrocarbon for

C X_{2} H X_{4}

, i.e.

y /4 \times 10 \times 2