A mixture of N2 (28) and SO2 (64) in mole ratio 1 : 2 effuses through a pinhole. The mole percent of N2 in the gas that first effuses (two decimals; take sqrt64/28 = 1.5119) is

JEE Advanced levelNumerical answerDifficulty 3 of 3ig152

A mixture of $N X_{2}$ (28) and $SO X_{2}$ (64) in mole ratio $1 : 2$ effuses through a pinhole. The mole percent of $N X_{2}$ in the gas that first effuses (two decimals; take $64/28 = 1.5119$ ) is

Numerical answer type, answer in %, tolerance 0.05.

Effusion amounts

\propto x_{i} / M_{i}

n_{N X_{2}} : n_{SO X_{2}} = \frac{1}{28} : \frac{2}{64} = 1.5119 : 2

. Mole fraction of

N X_{2}

= \frac{1.5119}{3.5119} = 0.4305

, i.e.

43.05

mole percent.