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JEE Advanced levelSingle correct optionDifficulty 3 of 3ig144

A gaseous mixture of $H X_{2}$ and $O X_{2}$ with $H X_{2}$ mole fraction $0.20$ effuses through a small hole. The mole fraction of $H X_{2}$ in the gas that effuses out initially is

A $0.50$
B $0.20$
C $0.80$
D $0.25$

Answer: A

Effused amounts are in the ratio

\frac{x _{H X_{2}} / 2}{x _{O X_{2}} / 32} = \frac{0.20}{0.80} \times 4 = 1

. So the effused gas has

H X_{2} : O X_{2} = 1 : 1

and the mole fraction of

H X_{2}

is

0.50

.

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