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JEE Main levelNumerical answerDifficulty 2 of 3ig135

A gas X effuses at one fourth the rate of $H X_{2}$ (molar mass 2) under identical conditions. The molar mass of X in $g mo l^{- 1}$ (nearest integer) is

Numerical answer type, answer in g/mol, tolerance 0.5.

Answer: 32 g/mol

\frac{r _{X}}{r _{H X_{2}}} = \frac{2}{M _{X}} = \frac{1}{4}

, so

M_{X} = 2 \times 16 = 32 g mo l^{- 1}

(oxygen).

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