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JEE Main levelSingle correct optionDifficulty 2 of 3ig123

$NH X_{3}$ (17) and $HCl$ (36.5) are introduced simultaneously at the two ends of a $1.0 m$ long tube. White fumes of $NH X_{4} Cl$ first appear nearer to

Athe $HCl$ end, at about $59 cm$ from the $NH X_{3}$ end
Bthe $NH X_{3}$ end, at about $41 cm$ from the $NH X_{3}$ end
Cthe midpoint
Dthe $HCl$ end, at about $68 cm$ from the $NH X_{3}$ end

Answer: A

\frac{r _{NH X_{3}}}{r _{HCl}} = 36.5/17 = 1.465

. Distance from the

NH X_{3}

end

= 100 \times \frac{1.465}{2.465} = 59.4 cm

, i.e. nearer the

HCl

end.

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