Answer: D
The compound shown is sodium 2-methylpropanoate. The radicals formed are CHX3⋅ and (CHX3)X2CH⋅. Their couplings give ethane (Me-Me), 2-methylpropane (Me-iPr) and 2,3-dimethylbutane (iPr-iPr). Butane would need two ethyl radicals or a propyl radical, which cannot arise here, so it is not formed.