Numerical answer type, tolerance 0.5.
Answer: 5
The compound shown is bromoethane. With three halides (Me, Et, Pr) there are six couplings: Me-Me ethane, Me-Et propane, Me-Pr butane, Et-Et butane, Et-Pr pentane and Pr-Pr hexane. Me-Pr and Et-Et give the same compound, butane, so the distinct alkanes are ethane, propane, butane, pentane and hexane: 5.