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JEE Main levelSingle correct optionDifficulty 2 of 3hx024

Hydrolysis of $(CH X_{3}) X_{3} C - Br$ by dilute aqueous $NaOH$ follows the rate law rate $= k [(CH X_{3}) X_{3} CBr]$ . If $[(CH X_{3}) X_{3} CBr]$ is doubled and $[OH X^{-}]$ is tripled, the rate becomes

Athe original (unchanged)
B6 times the original
C3 times the original
D2 times the original

Answer: D

The rate law is first order in the halide and zero order in hydroxide (rate-determining ionisation,

S_{N} 1

). Doubling the halide doubles the rate; changing

[OH X^{-}]

has no effect. New rate

= 2 \times

original.

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