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MolSynapse / Question bank / Equivalent Concept and Titration / Acid-base titrations and double titration (NaOH, Na2CO3, NaHCO3)
JEE Advanced levelOne or more correct optionsDifficulty 3 of 3eq156

25.0 mL portions of the following 0.100 M solutions are titrated with 0.100 M HCl. Which statements are correct?

  1. AFor , the phenolphthalein end point is at 25.0 mL
  2. BFor , the methyl orange end point is at 75.0 mL (total)
  3. CFor , the methyl orange end point is at 25.0 mL
  4. DFor a 25.0 mL solution that is 0.100 M in both NaOH and , the phenolphthalein end point is at 50.0 mL

Answer: A, C, D

: 2.50 mmol, first stage needs 2.50 mmol HCl = 25.0 mL (true), total to = 5.00 mmol = 50.0 mL, not 75.0 mL (false). : 2.50 mmol needs 25.0 mL (true). NaOH + : phenolphthalein stage = 2.50 + 2.50 = 5.00 mmol = 50.0 mL (true).
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