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MolSynapse / Question bank / Equivalent Concept and Titration / Acid-base titrations and double titration (NaOH, Na2CO3, NaHCO3)

JEE Main levelOne or more correct optionsDifficulty 2 of 3eq041

$1.325 g$ of pure $Na X_{2} CO X_{3}$ (molar mass $106 g mo l^{- 1}$ ) is titrated with $0.500 M$ $HCl$ . Select the correct statement(s).

AThe volume of $HCl$ needed for the methyl orange end point is $50.0 mL$
BThe volume of $HCl$ needed for the phenolphthalein end point is $25.0 mL$
CThe volume of $HCl$ needed for the phenolphthalein end point is $50.0 mL$
DThe sample contains $0.0125$ mol of $Na X_{2} CO X_{3}$

Answer: A, B, D

Moles of

Na X_{2} CO X_{3} = 1.325/106 = 0.0125

. Methyl orange takes

2 H X^{+}

per carbonate:

2 \times 0.0125/0.500 = 50.0 mL

. Phenolphthalein takes only

1 H X^{+}

:

25.0 mL

, so option 3 is wrong.

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