A solution is known to contain NaOH, Na2CO3 and NaHCO3 in at most two-component combinations. Titration with HCl gives V

Question

A solution is known to contain NaOH, Na2CO3 and NaHCO3 in at most two-component combinations. Titration with HCl gives V1 mL to the phenolphthalein end point and a further V2 mL to the methyl orange end point (same HCl). Which conclusions are correct?

Accepted Answer

V1 = 12.0 mL and V2 = 12.0 mL: only Na2CO3 is present

Accepted Answer

V1 = 20.0 mL and V2 = 8.0 mL: NaOH and Na2CO3 are present in mole ratio 3 : 2

Accepted Answer

V1 = 10.0 mL and V2 = 26.0 mL: NaHCO3 and Na2CO3 are present in mole ratio 8 : 5

Answer

V1 = 0 and V2 = 15.0 mL: NaOH and NaHCO3 are both present

A solution is known to contain NaOH, $Na X_{2} CO X_{3}$ and $NaHCO X_{3}$ in at most two-component combinations. Titration with HCl gives V1 mL to the phenolphthalein end point and a further V2 mL to the methyl orange end point (same HCl). Which conclusions are correct?

Answer: A, B, C

More questions on Acid-base titrations and double titration (NaOH, Na2CO3, NaHCO3)

A solution is known to contain NaOH, NaX2​COX3​ and NaHCOX3​ in at most two-component combinations. Titration with HCl gives V1 mL to the phenolphthalein end point and a further V2 mL to the methyl orange end point (same HCl). Which conclusions are correct?

Answer: A, B, C

More questions on Acid-base titrations and double titration (NaOH, Na2CO3, NaHCO3)

A solution is known to contain NaOH, $Na X_{2} CO X_{3}$ and $NaHCO X_{3}$ in at most two-component combinations. Titration with HCl gives V1 mL to the phenolphthalein end point and a further V2 mL to the methyl orange end point (same HCl). Which conclusions are correct?