20 mL of 0.2 M NaOH is neutralised by 0.05 M H2SO4. The volume of acid required is:

NEET levelSingle correct optionDifficulty 1 of 3eq039

$20 mL$ of $0.2 M$ $NaOH$ is neutralised by $0.05 M$ $H X_{2} SO X_{4}$ . The volume of acid required is:

H X_{2} SO X_{4}

(

n = 2

) of

0.05 M

0.10 N

, and

NaOH

0.2 N

. From

N_{1} V_{1} = N_{2} V_{2}

0.2 \times 20 = 0.10 \times V

, so

V = 40 mL