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JEE Advanced levelOne or more correct optionsDifficulty 3 of 3eq150

A 200 mL solution contains 0.020 mol and 0.010 mol HCl. Which statements are correct?

  1. AThe normality of the solution is 0.25 N
  2. BComplete neutralisation needs 0.050 mol NaOH
  3. CComplete neutralisation needs 0.025 mol
  4. D50.0 mL of the solution needs 12.5 mL of 0.50 M NaOH for neutralisation

Answer: A, B, C

Equivalents = 0.020 2 + 0.010 = 0.050, so N = 0.050/0.200 = 0.25 N (true) and NaOH needed = 0.050 mol (true). has n = 2, so 0.050/2 = 0.025 mol (true). 50.0 mL holds 12.5 meq, needing 12.5/0.50 = 25.0 mL of 0.50 M NaOH, not 12.5 mL (false).
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