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MolSynapse / Question bank / Equivalent Concept and Titration / Acid-base titrations and double titration (NaOH, Na2CO3, NaHCO3)
JEE Advanced levelSingle correct optionDifficulty 3 of 3eq151

A solution contains only NaOH and . Titrated with HCl, phenolphthalein is decolourised after 20.0 mL; methyl orange is then added and a further 7.5 mL is needed. The mole ratio in the solution is:

  1. A5 : 3
  2. B8 : 3
  3. C5 : 6
  4. D2 : 1

Answer: A

The further volume V2 = 7.5 mL converts to , and equals the volume that converted to . So 7.5, and NaOH V1 - V2 = 20.0 - 7.5 = 12.5. Ratio = 12.5 : 7.5 = 5 : 3.
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More questions on Acid-base titrations and double titration (NaOH, Na2CO3, NaHCO3)