Metal M (Z = 26) forms the ion M^3+ and metal N (Z = 24) forms the ion N^3+. Using mu = sqrtn(n+2) BM for the free gaseous ions, calculate the ratio mu(M^3+)/mu(N^3+) to two decimal places.

JEE Advanced levelNumerical answerDifficulty 3 of 3df034

Metal M ( $Z = 26$ ) forms the ion $M X^{3 +}$ and metal N ( $Z = 24$ ) forms the ion $N X^{3 +}$ . Using $μ = n (n + 2) BM$ for the free gaseous ions, calculate the ratio $μ (M X^{3 +}) / μ (N X^{3 +})$ to two decimal places.

Numerical answer type, tolerance 0.01.

Fe X^{3 +}

3 d^{5}

with

n = 5

, so

μ = 35 = 5.916 BM

Cr X^{3 +}

3 d^{3}

with

n = 3

, so

μ = 15 = 3.873 BM

. Ratio =

5.916/3.873 = 1.53