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JEE Advanced levelOne or more correct optionsDifficulty 3 of 3cc152

For the series $CoCl X_{3} \cdot n NH X_{3}$ with Co coordination number 6 (n = 3, 4, 5, 6), which statements are correct? One or more options may be correct.

AFor n = 6, all three chlorides are precipitated by $AgNO X_{3}$ and the cation has no stereoisomers.
BFor n = 3, the compound gives 1 mol of $AgCl$ per mole.
CFor n = 4, the cation shows geometrical isomerism and 1 mol of $AgCl$ forms per mole.
DFor n = 5, three ions per formula unit are formed and 2 mol of $AgCl$ form per mole.

Answer: A, C, D

n = 6:

[Co (NH X_{3}) X_{6}] Cl X_{3}

gives 3 AgCl and

Ma X_{6}

has one arrangement (true). n = 3:

[Co (NH X_{3}) X_{3} Cl X_{3}]

has no free chloride, so 0 AgCl (false). n = 4:

[Co (NH X_{3}) X_{4} Cl X_{2}] Cl

gives 1 AgCl and cis/trans forms (true). n = 5:

[Co (NH X_{3}) X_{5} Cl] Cl X_{2}

gives 3 ions and 2 AgCl (true).

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