A mixture contains 0.0150 mol of CoCl3.5NH3 and 0.0100 mol of CoCl3.4NH3 (Co coordination number 6 in both). The mass of AgCl (143.5 g/mol) precipitated by excess AgNO3, in g, is

JEE Advanced levelSingle correct optionDifficulty 3 of 3cc151

A mixture contains $0.0150$ mol of $CoCl X_{3} \cdot 5 NH X_{3}$ and $0.0100$ mol of $CoCl X_{3} \cdot 4 NH X_{3}$ (Co coordination number 6 in both). The mass of $AgCl$ (143.5 g/mol) precipitated by excess $AgNO X_{3}$ , in g, is

CoCl X_{3} \cdot 5 NH X_{3}

[Co (NH X_{3}) X_{5} Cl] Cl X_{2}

(2 free Cl) and

CoCl X_{3} \cdot 4 NH X_{3}

[Co (NH X_{3}) X_{4} Cl X_{2}] Cl

(1 free Cl). Moles of

AgCl = 0.0150 \times 2 + 0.0100 \times 1 = 0.0400

. Mass

= 0.0400 \times 143.5 = 5.74