For the scheme $A I$ ( $k_{1} = 0.060 s^{- 1}$ ), $I A$ ( $k_{- 1} = 0.50 s^{- 1}$ ), $I P$ ( $k_{2} = 0.25 s^{- 1}$ ), all first order, apply the steady-state approximation to I. When $[A] = 0.80 M$ , find the rate of formation of P in units of $1 0^{- 3} M s^{- 1}$ (two decimal places).

Numerical answer type, answer in 1e-3 M/s, tolerance 0.01.

Answer: 16 1e-3 M/s

Steady state:

k_{1} [A] = (k_{- 1} + k_{2}) [I]

, so

[I] = 0.060 \times 0.80/ (0.50 + 0.25) = 0.064 M

. Rate of formation of P

= k_{2} [I] = 0.25 \times 0.064 = 0.0160 M s^{- 1} = 16.00 \times 1 0^{- 3} M s^{- 1}