MolSynapse
question bank
All chapters
NEET
JEE
Practice
MolSynapse
/
Question bank
/
Chemical Kinetics
/
Rate of reaction, rate law, order and molecularity
NEET level
Single correct option
Difficulty 1 of 3
ck178
In the Haber reaction
N
X
2
+
3
H
X
2
2
NH
X
3
, ammonia forms at a rate of
0.60
mol
L
−
1
mi
n
−
1
. At what rate (in
mol
L
−
1
mi
n
−
1
) is hydrogen consumed?
A
0.60
B
0.40
C
1.80
D
0.90
Answer: D
Rates of change scale with the stoichiometric coefficients:
−
d
[
H
X
2
]
/
d
t
:
d
[
NH
X
3
]
/
d
t
=
3
:
2
. So
−
d
[
H
X
2
]
/
d
t
=
(
3/2
)
(
0.60
)
=
0.90
mol
L
−
1
mi
n
−
1
.
Practice Chemical Kinetics
More on Rate of reaction, rate law, order and molecularity
Previous question
Next question
More questions on Rate of reaction, rate law, order and molecularity
Mechanism for NO2 + CO -> NO + CO2: slow 2NO2 -> NO3 + NO with step rate = k[NO2]^2, k = 0.50 M^-1 s^-1; fast NO3 + CO -> NO2 + CO2. At [NO2...
JEE Advanced level
Acid-catalysed conversion: S + H+ <=> SH+ (fast, constant K), then SH+ + H2O -> P + H+ (slow, solvent in large excess). Experiment 1 uses [S...
JEE Advanced level
A mechanism for A + 2B -> D is: step 1 (slow) A + B -> C; step 2 (fast) C + B -> D, where C is an intermediate. The rate law is
JEE Main level
The decomposition 2H2O2 -> 2H2O + O2 of 50.0 mL of solution gives 33.6 mL of O2 (at STP, molar volume 22.4 L mol^-1) in the first 10.0 min. ...
JEE Main level
For 3A -> 2B, B is formed at 0.060 M s^-1. The rate of disappearance of A, in M s^-1, is
JEE Main level
For the scheme A -> I (k_1 = 0.060 s^-1), I -> A (k_-1 = 0.50 s^-1), I -> P (k_2 = 0.25 s^-1), all first order, apply the steady-state appro...
JEE Advanced level