Ozone decomposition 2O3 -> 3O2 proceeds by: fast equilibrium O3 O2 + O (constant K), then slow O + O3 -> 2O2 (constant k_2). Select the correct statement(s).

The order with respect to O3 is 2.

The order with respect to O2 is -1.

Adding extra O2 increases the rate.

The order with respect to O3 is 2.

The order with respect to O2 is -1.

JEE Advanced levelOne or more correct optionsDifficulty 3 of 3ck189

Ozone decomposition $2 O X_{3} 3 O X_{2}$ proceeds by: fast equilibrium $O X_{3} O X_{2} + O$ (constant $K$ ), then slow $O + O X_{3} 2 O X_{2}$ (constant $k_{2}$ ). Select the correct statement(s).

Slow step: rate

= k_{2} [O] [O X_{3}]

and

[O] = K [O X_{3}] / [O X_{2}]

, so rate

= k_{2} K [O X_{3}]^{2} [O X_{2}]^{- 1}

. Orders are

2

and

- 1

, overall

2 - 1 = 1

. Extra

O X_{2}

pushes the pre-equilibrium back, lowering

[O]

and the rate.