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Chemical Equilibrium
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Degree of dissociation and vapour density
JEE Main level
Numerical answer
Difficulty 2 of 3
ce183
N
X
2
O
X
4
(
g
)
2
NO
X
2
(
g
)
is 20\% dissociated at a total pressure of
1.0
atm
. Find
K
p
in atm, to two decimal places.
Numerical answer type, answer in atm, tolerance 0.01.
Answer: 0.17 atm
K
p
=
4
α
2
P
/
(
1
−
α
2
)
=
4
(
0.04
)
(
1.0
)
/0.96
=
0.1667
atm
, i.e. 0.17 atm.
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