JEE Main levelOne or more correct optionsDifficulty 2 of 3ce186
An equilibrium mixture obtained from PClX5(g)PClX3(g)+ClX2(g) has vapour density 80; the calculated value for undissociated PClX5 is 104.25. Select the correct statements.
AThe degree of dissociation is about 0.30
BThe number of moles of gas at equilibrium is about 1.30 per mole of PClX5 taken
CAt the same temperature, the observed vapour density would be higher if the equilibrium were established at a higher total pressure
DThe average molar mass of the equilibrium mixture is 80g/mol
Answer: A, B, C
α=(104.25−80)/80=0.303, so (A) holds and total moles =1+α=1.303, so (B) holds. Higher pressure suppresses dissociation (fewer moles), so d rises toward 104.25: (C) holds. Average molar mass =2d=160g/mol, so (D) is false.