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Degree of dissociation and vapour density
JEE Main level
Single correct option
Difficulty 2 of 3
ce181
PCl
X
5
is 40\% dissociated at a total equilibrium pressure of
2.0
atm
for
PCl
X
5
(
g
)
PCl
X
3
(
g
)
+
Cl
X
2
(
g
)
.
K
p
(in atm) is
A
0.53
B
0.19
C
0.89
D
0.38
Answer: D
K
p
=
α
2
P
/
(
1
−
α
2
)
=
(
0.16
×
2.0
)
/0.84
=
0.381
atm
. Using
1
−
α
instead of
1
−
α
2
gives 0.53.
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