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JEE Main levelSingle correct optionDifficulty 2 of 3ce180

Vapours of $NH X_{4} Cl$ (calculated vapour density $26.75$ for undissociated $NH X_{4} Cl$ ) have an observed vapour density of $15$ at a certain temperature through $NH X_{4} Cl (g) NH X_{3} (g) + HCl (g)$ . The degree of dissociation is

A $0.78$
B $0.56$
C $0.44$
D $1.78$

Answer: A

α = (D - d) / d = (26.75 - 15) /15 = 0.783

, about 0.78.

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