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Basic Inorganic Nomenclature and Oxidation Number
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Oxidation number determination including fractional and unusual cases
JEE Main level
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Difficulty 2 of 3
bn141
In which of the following does the specified atom have an AVERAGE oxidation number of exactly
+
2
?
A
Fe in
K
X
4
[
Fe
(
CN
)
X
6
]
B
Ni in
Ni
(
CO
)
X
4
C
S in
S
X
2
O
X
3
X
2
−
(average of both S atoms)
D
Cu in
CuSO
X
4
⋅
5
H
X
2
O
Answer: A, C, D
Fe:
x
−
6
=
−
4
, so
+
2
. Ni in
Ni
(
CO
)
X
4
is
0
because CO is neutral. S in
S
X
2
O
X
3
X
2
−
:
2
x
−
6
=
−
2
, so
+
2
. Cu in
CuSO
X
4
is
+
2
.
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