Match each species (Column I) with the oxidation number of N (Column II). Column I: P N2H4, Q NH2OH, R N2O, S NO2. Column II: 1 +4, 2 +1, 3 -1, 4 -2 (H is +1, O is -2).

JEE Main levelSingle correct optionDifficulty 2 of 3bn139

Match each species (Column I) with the oxidation number of N (Column II). Column I: P $N X_{2} H X_{4}$ , Q $NH X_{2} OH$ , R $N X_{2} O$ , S $NO X_{2}$ . Column II: 1 $+ 4$ , 2 $+ 1$ , 3 $- 1$ , 4 $- 2$ (H is $+ 1$ , O is $- 2$ ).

N X_{2} H X_{4}

2 x + 4 = 0

x = - 2

NH X_{2} OH

x + 2 - 2 + 1 = 0

x = - 1

N X_{2} O

2 x - 2 = 0

x = + 1

NO X_{2}

x - 4 = 0

x = + 4

. So P-4, Q-3, R-2, S-1.