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Basic Inorganic Nomenclature and Oxidation Number
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Oxidation number determination including fractional and unusual cases
JEE Main level
Single correct option
Difficulty 2 of 3
bn137
In sodium borohydride,
NaBH
X
4
, hydrogen is present as hydride (
−
1
) and Na is
+
1
. What is the oxidation number of B?
A
+
3
B
−
3
C
+
5
D
+
1
Answer: A
The oxidation numbers must add up to zero.
1
+
x
+
4
(
−
1
)
=
0
gives
x
=
+
3
.
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