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JEE Advanced levelOne or more correct optionsDifficulty 3 of 3bn041

Select the CORRECT comparisons of oxidation numbers (O is $- 2$ , K and Na are $+ 1$ , cyanide is $CN X^{-}$ ).

AMn in $K X_{2} MnO X_{4}$ equals Cr in $K X_{2} CrO X_{4}$
BCl in $Cl X_{2} O X_{7}$ is greater than Cl in $ClO X_{2}$
CN in $N X_{2} O$ is greater than N in $NO X_{2} X^{-}$
DFe in $K X_{4} [Fe (CN) X_{6}]$ equals Fe in $FeSO X_{4}$

Answer: A, B, D

(a) Mn in

K X_{2} MnO X_{4}

and Cr in

K X_{2} CrO X_{4}

are both

+ 6

. (b) Cl in

Cl X_{2} O X_{7}

is

+ 7

and in

ClO X_{2}

is

+ 4

, so the first is greater. (c) N in

N X_{2} O

is

+ 1

and in

NO X_{2} X^{-}

is

+ 3

, so the first is smaller, not greater. (d) Fe is

+ 2

in both

K X_{4} [Fe (CN) X_{6}]

and

FeSO X_{4}

.

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