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Basic Inorganic Nomenclature and Oxidation Number
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Oxidation number determination including fractional and unusual cases
JEE Advanced level
One or more correct options
Difficulty 3 of 3
bn038
Select the species in which the named element is in the
+
5
oxidation state (H is
+
1
, Na is
+
1
, O is
−
2
).
A
P in
HPO
X
3
B
P in
H
X
4
P
X
2
O
X
7
C
Cl in
ClO
X
3
X
−
D
P in
Na
X
2
HPO
X
3
Answer: A, B, C
HPO
X
3
:
1
+
x
−
6
=
0
gives P
+
5
.
ClO
X
3
X
−
:
x
−
6
=
−
1
gives Cl
+
5
.
H
X
4
P
X
2
O
X
7
:
4
+
2
x
−
14
=
0
gives P
+
5
.
Na
X
2
HPO
X
3
:
2
+
1
+
x
−
6
=
0
gives P
+
3
.
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