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Basic Inorganic Nomenclature and Oxidation Number
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Oxidation number determination including fractional and unusual cases
JEE Advanced level
Single correct option
Difficulty 3 of 3
bn040
Using F
=
−
1
and O
=
−
2
, what is (oxidation number of Xe in
XeO
X
3
F
X
2
) minus (oxidation number of Xe in
XeOF
X
4
)?
A
4
B
0
C
14
D
2
Answer: D
XeOF
X
4
:
x
−
2
−
4
=
0
gives
+
6
.
XeO
X
3
F
X
2
:
x
−
6
−
2
=
0
gives
+
8
. The difference is
8
−
6
=
2
.
Practice Basic Inorganic Nomenclature and Oxidation Number
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