JEE Advanced levelSingle correct optionDifficulty 3 of 3as039
A monochromatic source delivers 2.0mW of light of wavelength 400nm to a photocell. Only 0.50% of the incident photons eject an electron, and every ejected electron is collected. Use h=6.626×10−34Js, c=3.0×108ms−1, e=1.6×10−19C. The photocurrent is closest to
A3.22 μA
B0.00 mA
C322 μA
D6.44 μA
Answer: A
Photon energy = hc/λ = 4.9695e-19 J. Photons per second = 2.0e-3/4.9695e-19 = 4.025e+15. Electrons per second = 0.005 x 4.025e+15 = 2.012e+13. Current = 2.012e+13 x 1.6e-19 = 3.220e-06 A = 3.22 microamp.