For a certain metal the stopping potential for light of wavelength $300 nm$ is exactly 3 times that for light of wavelength $500 nm$ . The work function of the metal is closest to (use $h = 6.626 \times 1 0^{- 34} J s$ , $c = 3.0 \times 1 0^{8} m s^{- 1}$ , $1 eV = 1.6 \times 1 0^{- 19} J$ )

A2.90 eV
B1.66 eV
C0.83 eV
D2.48 eV

Answer: B

Photon energies: 4.141 eV (300 nm) and 2.485 eV (500 nm). With V1 = 3 V2: 4.141 - W = 3(2.485 - W). So 2W = 3(2.485) - 4.141 = 3.313, giving W = 1.66 eV.

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For a certain metal the stopping potential for light of wavelength 300 nm is exactly 3 times that for light of wavelength 500 nm. The work function of the metal is closest to (use h=6.626×10−34 Js, c=3.0×108 ms−1, 1 eV=1.6×10−19 J)

Answer: B

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For a certain metal the stopping potential for light of wavelength $300 nm$ is exactly 3 times that for light of wavelength $500 nm$ . The work function of the metal is closest to (use $h = 6.626 \times 1 0^{- 34} J s$ , $c = 3.0 \times 1 0^{8} m s^{- 1}$ , $1 eV = 1.6 \times 1 0^{- 19} J$ )